Answer:
[tex]+4.8\cdot 10^{-19}C[/tex]
Explanation:
The initial charge of the object is zero, since the object is neutral:
Q = 0
When we remove three electrons, we remove a charge of:
[tex]q' = 3 \cdot q_e[/tex]
where
[tex]q_e = 1.6\cdot 10^{-19}C[/tex] is the charge of one electron. Substituting,
[tex]q'=3 \cdot 1.6\cdot 10^{-19}C=-4.8\cdot 10^{-19} C[/tex]
So, the final charge on the initially neutral object will be
[tex]q=Q-q' = 0 - (-4.8\cdot 10^{-19} C)=+4.8\cdot 10^{-19}C[/tex]
