The temperature in Miami, Florida is 22 degrees warmer than three times the temperature in Bangor, Maine. The temperature in Miami is 82 degrees. Write an equation to determine the temperature in Bangor. 3x + 82 = 22 3x + 22 = 82 3x − 22 = 82 3x − 82 = 22

Respuesta :

Answer:

[tex]y=\frac{x-22}{3} ; y=20[/tex]

Step-by-step explanation:

Let Temperature of Maimi [tex]T_{m}[/tex]  and that of Bangor be [tex]T_{b}[/tex]

Given in the condition is [tex]T_{m}[/tex] is 22 more than 3 times  [tex]T_{b}[/tex]

i.e. [tex]T_{m}[/tex] = 22+ 3 * [tex]T_{b}[/tex]

Hence

[tex]T_{m} - 22 = 3 * T_{b}[/tex]

[tex]T_{b} = \frac{T_{m}-22}{3}[/tex]

Here also we are given that [tex]T_{m}[/tex]=82

[tex]T_{b} = \frac{82-22}{3}[/tex]

[tex]T_{b} = \frac{60}{3}[/tex]

[tex]T_{b} = 20[/tex]

If the temperature in Miami is 82 degrees, then the temperature in Bangor is 20 degrees

Further explanation

From the statement: "The temperature in Miami, Florida is 22 degrees warmer than three times the temperature in Bangor, Maine", we could write the equation such as below :

[tex]M = 22 + 3B[/tex]

where :

B = temperature in Bangor

M = temperature in Miami

From the above equation , we could rearrange it to get the temperature in Bangor.

[tex]M = 22 + 3B[/tex]

[tex]M - 22 = 22 - 22 + 3B[/tex]

[tex]M - 22 = 3B[/tex]

[tex]\frac{1}{3}(M - 22) = \frac{1}{3}(3B)[/tex]

[tex]B = \frac{1}{3}(M - 22)[/tex]

where :

B = temperature in Bangor

M = temperature in Miami

At last , we substitute the temperature in Miami ( M ) 82 degrees into the equation :

[tex]B = \frac{1}{3}(M - 22)[/tex]

[tex]B = \frac{1}{3}(82 - 22)[/tex]

[tex]B = \frac{1}{3}(60)[/tex]

[tex]\boxed {B = 20~degrees}[/tex]

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Answer details

Grade: Middle School

Subject: Mathematics

Chapter: Linear Equation

Keywords: Temperature , Miami , Florida , Bangor , Maine , Equation , Algebra , Linear