A line has a slope of
Which ordered pairs could be points on a parallel line? Check all that apply.
(-8, 8) and (2, 2)
(-5, -1) and (0, 2)
(-3, 6) and (6.-9)
(-2, 1) and (3,-2)
(0, 2) and (5,5)

A line has a slope of Which ordered pairs could be points on a parallel line Check all that apply 8 8 and 2 2 5 1 and 0 2 3 6 and 69 2 1 and 32 0 2 and 55 class=

Respuesta :

Answer:

B and D

Step-by-step explanation:

Given a line with slope m = - [tex]\frac{3}{5}[/tex]

Since the lines are parallel we require the points with the same slope

Using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = 8, 8) and (x₂, y₂ ) = (2, 2)

m = [tex]\frac{2-8}{2-8}[/tex] = 1 ← not parallel

Repeat with (x₁, y₁ ) = (5, - 1) and (x₂, y₂ ) = (0, 2)

m = [tex]\frac{2+1}{0-5}[/tex] = - [tex]\frac{3}{5}[/tex] ← Parallel

with (x₁, y₁ ) = (- 3, 6) and (x₂, y₂ ) = (6, - 9)

m = [tex]\frac{-9-6}{6+3}[/tex] = - [tex]\frac{5}{3}[/tex] ← not parallel

with (x₁, y₁ ) = (- 2, 1) and (x₂, y₂ ) = (3, - 2)

m = [tex]\frac{-2-1}{3+2}[/tex] = - [tex]\frac{3}{5}[/tex] ← Parallel

with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (5, 5)

m = [tex]\frac{5-2}{5-0}[/tex] = [tex]\frac{3}{5}[/tex] ← not parallel