What is the length of AC? Round to the nearest tenth.
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Answer:
AC ≈ 10.5 cm (1 dec. place )
Step-by-step explanation:
Given
tan55° = [tex]\frac{15}{b}[/tex]
Multiply both sides by b
b × tan55° = 15 ( divide both sides by tan55° )
AC = b = [tex]\frac{15}{tan55}[/tex] ≈ 10.5 cm