Answer:
[tex]49.7^{\circ}[/tex]
Explanation:
We can solve the problem by using Snell's law:
[tex]n_1 sin \theta_1 = n_2 sin \theta_2[/tex]
where
n1 = 1.33 is the index of refraction of the first medium (water)
n2 = 1.00 is the index of refraction of the second medium (air)
[tex]\theta_1 = 35^{\circ}[/tex] is the angle of incidence of the wave in water
[tex]\theta_2[/tex] is the angle of refraction of the wave in air
Solving for the angle of refraction,
[tex]sin \theta_2 = \frac{n_1 sin \theta_1}{n_2}=\frac{(1.33) sin 35^{\circ}}{1.00}=0.763\\\theta_2 = sin^{-1} (0.763)=49.7^{\circ}[/tex]
