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"Each value below represents a different aqueous solution at 25 °C. Classify each solution as acidic, basic, or?Are the following acidic, basic or nuetral? pOH=3.37 pOH=11.40 [h+]=3.8x10^-4 [h+]=5.8x10^-8 [OH-]=3.5x10^-12 [OH-]=6.6x10^-3 [h+]=1.0x10^-7 pOh=7 pH=5.11 pH=12.94"

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superman1987

Answer:

1) pOH = 3.37                The solution is basic.

2) pOH = 11.40              The solution is acidic.

3) [H⁺] = 3.8 x 10⁻⁴        The solution is acidic.

4) [H⁺] = 5.8 x 10⁻⁸        The solution is basic.

5) [OH⁻] = 3.5 x 10⁻¹²    The solution is acidic.

6) [OH⁻] = 6.6 x 10⁻³     The solution is basic.

7) [H⁺] = 1.0 x 10⁻⁷         The solution is neutral.

8) pOH = 7                    The solution is neutral.

9) pH = 5.11                   The solution is acidic.

10) pH=12.94                The solution is basic.

Explanation:

  • We can determine the nature of the solution, acidic, basic or neutral, from the value of the pH.

pH is a sclale from 0 to 14.

  • If pH < 7, the solution is acidic.
  • If pH = 7, the solution is neutral.
  • If pH > 7, the solution basic.

1) pOH = 3.37:

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 3.37 = 10.63.

∵ pH > 7.

∴ The solution is basic.

2) pOH = 11.40:

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 11.40 = 2.60.

∵ pH < 7.

∴ The solution is acidic.

3) [H⁺] = 3.8 x 10⁻⁴:

∵ pH = - log[H⁺].

[H⁺] = 3.8 x 10⁻⁴ M.

∴ pH = - log(3.8 x 10⁻⁴ M) = 3.42.

∵ pH < 7.

∴ The solution is acidic.

4) [H⁺] = 5.8 x 10⁻⁸:

∵ pH = - log[H⁺].

[H⁺] = 5.8 x 10⁻⁸ M.

∴ pH = - log(5.8 x 10⁻⁸ M) = 7.236.

∵ pH > 7.

∴ The solution is basic.

5) [OH⁻] = 3.5 x 10⁻¹²:

∵ pOH = - log[OH⁻].

[OH⁻] = 3.5 x 10⁻¹² M.

∴ pOH = - log(3.5 x 10⁻¹² M) = 11.46.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 11.46 = 2.54.

∵ pH < 7.

∴ The solution is acidic.

6) [OH⁻] = 6.6 x 10⁻³:

∵ pOH = - log[OH⁻].

[OH⁻] = 6.6 x 10⁻³ M.

∴ pOH = - log(6.6 x 10⁻³ M) = 2.18.

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 2.18 = 11.82.

∵ pH > 7.

∴ The solution is basic.

7) [H⁺] = 1.0 x 10⁻⁷:

∵ pH = - log[H⁺].

[H⁺] = 1.0 x 10⁻⁷ M.

∴ pH = - log(1.0 x 10⁻⁷ M) = 7.0.

∵ pH = 7.

∴ The solution is neutral.

8) pOH = 7:

∵ pH + pOH = 14.

∴ pH = 14 - pOH = 14 - 7.0 = 7.0.

∵ pH = 7.

∴ The solution is neutral.

9) pH = 5.11:

∵ pH < 7.

∴ The solution is acidic.

10) pH = 12.94:

∵ pH > 7.

∴ The solution is basic.

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