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Janet can do a job in three hours while Gary can do the same job in two hours. If Janet works for an hour before Gary be in helping her how long will it take them to finish the job together?

Respuesta :

harpazo

Janet = 1/3

Gary = 1/2

(1/3) + (1/2) = 5/6

Let x = time they both can do the job together

(1/2) + (5/6)x = 1

Solve for x to find your answer.

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