Solve for x in the equation y^2 + 2x + 1 = 17.
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Answer:
B
Step-by-step explanation:
So your equation is actually x^2+2x+1=17
Left hand side is already set for rewriting it as a perfect square
So you have actually that (x+1)^2=17
Now you just take square root of both sides
x+1=(pm) sqrt(17) (pm) means plus or minus
x=-1 (pm) sqrt(17) I subtracted 1 on both sides
B