Answer: (-a-b, c)
Step-by-step explanation:
We know that the mid point of a line having endpoints [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by :-
[tex]x=\dfrac{x_1+x_2}{2}\ , \ y=\dfrac{y_1+y_2}{2}[/tex]
In the given figure it can be seen that D is the midpoint of RT :
Since R(-2b , 2c) and T(-2a, 0)
Then , the midpoint D of a line having endpoints [tex](-2b,2c)[/tex] and [tex](-2a,0)[/tex] is given by :-
[tex]x=\dfrac{-2b+(-2a)}{2}=\dfrac{2(-a-b)}{2}=-a-b\ , \ y=\dfrac{2c+0}{2}=c[/tex]
Hence , the coordinates of midpoint D = (-a-b, c)