Answer:
No, the point [tex](2,3)[/tex] is not a solution to the system of equation [tex]x2+y2=13[/tex] and [tex]2x-y=4[/tex].
Step-by-step explanation:
To make sure it is, it has to work on both equation. Plugging this into the first and second equations respectivly gives us:
[tex]13=x2+y2=(2)2+(3)2=4+6=10[/tex]
[tex]4=2x-y=2(2)-(3)=4-3=1[/tex]
Since [tex]13\neq10[/tex] and [tex]4\neq 1[/tex], the point [tex](2,3)[/tex] is not a solution to the system of equation [tex]x2+y2=13[/tex] and [tex]2x-y=4[/tex].
