Respuesta :
Answer:
[tex]\sqrt{13}[/tex]
Step-by-step explanation:
Given the vector < a, b > then the magnitude is
[tex]\sqrt{a^2+b^2}[/tex], thus
| (- 3, 2) | = [tex]\sqrt{(-3)^2+2^2}[/tex] = [tex]\sqrt{9+4}[/tex] = [tex]\sqrt{13}[/tex]
Answer:
The length of the magnitude of the given vector <-3,2> is:
[tex]\sqrt{13}[/tex]
Step-by-step explanation:
We know that for any vector of the type: <a,b>
The magnitude of the length of the vector is given by the formula:
[tex]|<a,b>|=\sqrt{a^2+b^2}[/tex] [tex]\sqrt{13}[/tex]
Here we are given the vector as: <-3,2>
i.e. a= -3
and b=2.
This means that the length of the magnotude of the vector is given by:
[tex]|<-3,2>|=\sqrt{(-3)^2+(2)^2}\\\\i.e.\\\\|<-3,2>|=\sqrt{9+4}\\\\i.e.\\\\|<-3,2>|=\sqrt{13}[/tex]
Hence, the answer is: [tex]\sqrt{13}[/tex]
