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An electric field can be created by a single charge or a distribution of charges. The electric field a distance from a point charge has magnitude E = k|q'|/r^2.The electric field points away from positive charges and toward negative charges. A distribution of charges creates an electric field that can be found by taking the vector sum of the fields created by individual point charges. Note that if a charge is placed in an electric field created by q', q will not significantly affect the electric field if it is small compared to q'.Imagine an isolated positive point charge with a charge Q (many times larger than the charge on a single electron).There is a single electron at a distance from the point charge. On which of the following quantities does the force on the electron depend?Check all that apply.A the distance between the positive charge and the electronB the charge on the electronC the mass of the electronD the charge of the positive chargeE the mass of the positive chargeF the radius of the positive chargeG the radius of the electron

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skyluke89

Answer:

A the distance between the positive charge and the electron

B the charge on the electron

D the charge of the positive charge

Explanation:

The electric field produced by the positive charge Q at the location of the electron is given by

[tex]E=k\frac{Q}{r^2}[/tex]

where

k is the Coulomb constant

Q is the charge

r is the distance between the charge Q and the electron

The force exerted on a charged particle by an electric field is given by

[tex]F=qE[/tex]

where q is the magnitude of the charged particle. So, the force exerted on the electron in this problem is

[tex]F=eE = k\frac{eQ}{r^2}[/tex]

where e is the charge of the electron. As we see from the equation, the force depends only the following quantities:

A the distance between the positive charge and the electron (r)

B the charge on the electron (e)

D the charge of the positive charge (Q)

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