contestada

The Cosmic Background Radiation Outer space is filled with a sea of photons, created in the early moments of the universe. The frequency distribution of this "cosmic background radiation" matches that of a blackbody at a temperature near 2.7K.What is the peak frequency of this radiation in Hz?What is the wavelength that corresponds to the peak frequency in mm?

Respuesta :

A) Peak wavelength: 1.07 mm

The peak wavelength of the Cosmic Background Radiation can be found by using Wien's displacement law:

[tex]\lambda = \frac{b}{T}[/tex]

where

[tex]\lambda[/tex] is the peak wavelength

[tex]b=2.898\cdot 10^{-3}m\cdot K[/tex] is Wien's displacement constant

T is the absolute temperature

For the Cosmic Background Radiation,

T = 2.7 K

So the peak wavelength is

[tex]\lambda = \frac{2.898\cdot 10^{-3}m\cdot K}{2.7 K}=1.07\cdot 10^{-3} m=1.07 mm[/tex]

B) Peak frequency: [tex]2.8\cdot 10^{11}Hz[/tex]

The peak frequency can be found by using the relationship:

[tex]f=\frac{c}{\lambda}[/tex]

where

[tex]c=3.0\cdot 10^8 m/s[/tex] is the speed of light

[tex]\lambda[/tex] is the peak wavelength

Substituting numbers, we find

[tex]f=\frac{3.0\cdot 10^8 m/s}{1.07\cdot 10^{-3} m}=2.8\cdot 10^{11}Hz[/tex]