Answer: [tex]\bold{D)\quad h^{-1}(x)=\dfrac{1}{6}(x-1)}[/tex]
Step-by-step explanation:
Inverse is when you swap the x's and y's and then solve for y
y = 6x + 1
x = 6y + 1 swapped the x's and y's
x - 1 = 6y subtracted 1 from both sides
[tex]\dfrac{1}{6}[/tex] (x - 1) = y divided both sides by 6
