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A cube of gold weights1.89N when suspended in air from a spring scale. When suspended in molasses, it appears to weight 1.76 N. What is the bouyancy force acting on the cube? Do you think the buoyancy force would bengreater or smaller if the gold cube were suspended in water?

Respuesta :

The buoyancy force acting on the cube will be  3.65 N and the buoyancy force would be greater if the gold cube were suspended in water.

What is buoyancy force?

A fluid exerts an upward force against the weight of a partly or completely submerged item.

The weight is acting downward if the weight of a cube of gold in the air is considered then the equation ios found as;

F = W+w

Where,

F is the buoyancy force

W is the weight of a cube in water

w is the weight of the cube in the air

The buoyancy force is found as;

F = W+w

F= 1.89 +1.76

F= 3.65 N

The formula for the buoyancy force is;

F=ρgV

If the density is greater the buoyancy force is greater the density of the water is greater than the air for the same condition the buoyancy force would be greater if the gold cube were suspended in water.

Hence, the buoyancy force acting on the cube will be 3.65 N and the buoyancy force would be greater if the gold cube were suspended in water.

To learn more about the buoyancy force refer to the link;

https://brainly.com/question/13267336

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