contestada

Find the limit of the function algebraically. limit as x approaches zero of quantity x cubed plus one divided by x to the fifth power.

Respuesta :

Space

Answer:

[tex]\displaystyle \lim_{x \to 0} \Big( x^3 + \frac{1}{x^5} \Big) = \text{und} \text{efined}[/tex]

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]:                                                             [tex]\displaystyle \lim_{x \to c} x = c[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \lim_{x \to 0} \Big( x^3 + \frac{1}{x^5} \Big)[/tex]

Step 2: Evaluate

  1. Limit Rule [Variable Direct Substitution]:                                                    [tex]\displaystyle \lim_{x \to 0} \Big( x^3 + \frac{1}{x^5} \Big) = 0^3 + \frac{1}{0^5}[/tex]
  2. Simplify:                                                                                                         [tex]\displaystyle \lim_{x \to 0} \Big( x^3 + \frac{1}{x^5} \Big) = \text{und} \text{efined}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

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