What is the positive difference between the square of the sum of the first five positive integers and the sum of the first five positive perfect squares?

Respuesta :

gmany

Answer:

200

Step-by-step explanation:

The square of the sum of the first five positive integers:

(1 + 2 + 3 + 4 + 5)² = 15² = 225

The sum of the first positive perfect square:

1² + 2² + 3² + 4² + 5² = 1 + 4 + 9 + 16 + 25 = 55

225 - 55 = 200

The positive difference between the square of the sum of the first five positive integers and the sum of the first five positive perfect squares is 170. This is obtained by taking the sum of first five numbers, squaring the sum and subtracting the sum of first five perfect squares.

Calculate the positive difference:

The sum of first five positive integers = 1+2+3+4+5 = 15

Square of the sum of the first five positive integers = 15² = 225

The sum of the first five positive perfect squares =1²+2²+3²+4²+5²

                                                                                 =1+4+9+16+25

                                                                                 =55

The positive differenece = 225-55=170

Hence the positive difference between the square of the sum of the first five positive integers and the sum of the first five positive perfect squares is 170.

Learn more about arithmetic sequence here:

brainly.com/question/20368522

#SPJ2