Answer:
Step-by-step explanation:
First let's calculate the probability of the sum of the cubes being 4, so we can subtract it from 100% to get the probability of the sum not being 4.
In order to be 4 we have the following outcomes.
Outcomes = {(1, 3), (2, 2)}, there are 2 outcomes out of 36 when the sum is equal to 4.
P(Sn4) = [tex]100 \% - \frac{2}{36} \cdot 100 \% = 100 \% - \frac{100 \%}{18} = 100 \% (1 - \frac{1}{18}) = 100 \% \cdot \frac{17}{18} \approx 94 \%[/tex]
Now to find the probability of the sum being greater than 5, we'll find the probability of it being less than or equal to 5.
Outcomes = {(1, 1), (1, 2), (1, 3), (1, 4), (2, 2), (2, 3)}, there are 6 outcomes out of 36.
Now to find the probability of the sum of the dice being greater than 5, we'll subtract the probability of the sum being less than or equal to 5 from 100%.
P(Bgt5) = [tex]100 \% - [\frac{6}{36} \cdot 100 \%] = 100 \% (1 - \frac{1}{6}) = 100 \% \cdot \frac{5}{6} \approx 83 \%[/tex]
