Answer:
Yes.
Step-by-step explanation:
By using Bezout's Theorem regarding polynomials, we can determine if 'x - 2' is a factor of the original P(x). The theorem states that if any polynomial P(X) is divided by x - a, where a - a real number. Then the remainder of the devision is precisely P(a). And if the remainder is 0, then that means x - a, or x - 2 in our case, is a factor of the riginal P(x).
P(2) = [tex]2^3 + 2 \cdot 2^2 - 6 \cdot 2 - 4 = 0[/tex]
Therefore x - 2 is a factor of P(x)
