What is y = tan θ when θ = π?
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Answer:
y = tan(π) = 0 ⇒ the third answer
Step-by-step explanation:
* Lets think how to solve the problem
∵ y = tanФ
∵ tanФ = sinФ/cosФ
∵ Ф = π
* Find sinπ and cosπ by find where is the angle π located
- The unit circle intersect x-axis at point (1 , 0) and (-1 , 0)
- The unit circle intersect y-axis at point (0 , 1) and (0 , -1)
∵ cosФ = x-coordinates of the points
∵ sinФ = y-coordinates of the points
- The positive part of x-axis has angle -2π , 0 , 2π
- The negative part of x-axis has angle -π , π
- The positive part of y-axis has angle -3π/2 , π/2
- The negative part of y-axis has angle -π/2 , 3π/2
∴ The angle of measure π lies on the -ve part of x-axis
∴ cos(π) = -1 and sin(π) = 0
* Lets substitute them in tanФ
∴ tan(π) = sin(π)/cos(π) = 0/-1 = 0
* y = tan(π) = 0