Answer:
The surface area of the award is [tex]132\ in^{2}[/tex]
Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
[tex]SA=6^{2}+4[\frac{1}{2}(6)(8)]=132\ in^{2}[/tex]
