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ShyzaSling

Answer:

option b

16π

Step-by-step explanation:

Given in the question an equation,

y = 3sin(x/8)

We know that, the period of y = asin(bx) is given by

Period = [tex]\frac{2\pi }{|b|}[/tex]

here,

a = 3

b = 1/8

so,

Period =  2π / (1/8)

           = 8(2π)

           = 16π

The period of the function is 16π .

Answer:

B. 16π

Step-by-step explanation:

Given a function in the form;

y = A sin(B(x + C)) + D

Then;

Amplitude is A and Period is 2π/B

In our case; the function is y = 3 sin(x/8)

Therefore; B = 1/8

Hence; Period = 2π/(1/8)

                        = 16π

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