Answer:
Should place the current perpendicular to the magnetic field
Explanation:
The magnetic force exerted on a current-carrying wire is given by
[tex]F=ILBsin \theta[/tex]
where
I is the current in the wire
L is the length of the wire
B is the magnetic field
[tex]\theta[/tex] is the angle between the direction of the wire and the magnetic field
As we see from the formula, the magnetic force is maximum when
[tex]sin \theta=1[/tex]
which means
[tex]\theta=90^{\circ}[/tex]
So, when the current in the wire and the magnetic field are perpendicular to each other.
The magnetic field is the type of field where the magnetic force is obtained. With the help of a magnetic field. The current should orient 90° relative to the magnetic field.
It is the type of field where the magnetic force is obtained. With the help of a magnetic field. The magnetic force is obtained it is the field felt around a moving electric charge.
The magnetic force exerted on a current-carrying wire is given by
[tex]\rm F=ILBsin\theta[/tex]
Where the denotation of letters is;
The current in the wire is I.
L is the wire's length.
B stands for the magnetic field.
Θ is the angle formed by the wire's direction and the magnetic field
The value sin is maximum when it is equal to 1 and it is possible when the value of Θ is 90°.
[tex]\rm sin\theta=1[/tex]
Hence the current should orient 90° relative to the magnetic field.
To learn more about the megnetic field refer to the link;
https://brainly.com/question/19542022
