Respuesta :

kudzordzifrancis

Answer:

C. 60

Step-by-step explanation:

From triangle ADB,

[tex]|AD|^2+|BD|^2=|AB|^2[/tex]

[tex]|AD|^2+16^2=20^2[/tex]

[tex]|AD|^2=20^2-16^2[/tex]

[tex]|AD|^2=400-256[/tex]

[tex]|AD|^2=144[/tex]

[tex]|AD|=\sqrt{144}[/tex]

[tex]|AD|=12[/tex]

From triangle ADC,

[tex]|CD|^2+12^2=15^2[/tex]

[tex]|CD|^2+144=225[/tex]

[tex]|CD|^2=225-144[/tex]

[tex]|CD|^2=81[/tex]

[tex]|CD|=9[/tex]

The perimeter is the distance around the figure.

The perimeter

[tex]=15+20+16+9[/tex]

[tex]=60[/tex]

carlosego

Answer: OPTION C

Step-by-step explanation:

Calculate the height  AD with Pythagorean Theorem:

[tex]AD=\sqrt{20^{2}-16^{2}}=12[/tex]

Calculate the base CD  with Pythagorean Theorem:

[tex]CD=\sqrt{15^{2}-12^{2}}=9[/tex]

The perimeter is the sum of all the sides, therefore the perimeter is:

[tex]P=9+15+16+20=60[/tex]

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