Answer 1:
FE is 53.55 cm long
Step-by-step explanation:
In this figure DF is hypotenuse , FE is perpendicular and DE is base
So we will use TanQ = perpendicular/Base
where Q is theta which is 57 here,
tanQ = FE/ DE,
Here DE is 35
tan(57) = FE/35
1.53 =FE/35
FE=1.53 X35
FE = 53.55
FE is 53.55 cm long.
Answer 2:
DF = 63.9
Step-by-step explanation:
By using pythagoras theorem
( H)^2 = (P)^2 + (B)^2
(DF) ^2 = (FE)^2 + (DE)^2
(DF)^2 = (53.55)^2 + (35)^2
(DF) ^2 =2867.6 + 1225
(DF)^2 = 4092.6
DF = 63.9
Answer 3:
RP = 53.3mm
Step-by-step explanation:
Given in the question as following,
Q (Q) = 53 QR =41mm
QR is base,
RP is perpendicular,
PQ is hypotenuse
TanQ = perpendicuar/base
Tan(53) =RP/QR
1.3 =RP/41
RP = 53.3mm
Answer 4:
(PQ) =75.16mm
Step-by-step explanation:
(PQ)^2 = (PR)^2+(QR)^2
(PQ)^2 = (53.3)^2+(53)^2
(PQ)^2 =2840.8 +2809
(PQ)^2 = 5649.8
(PQ) =75.16mm
Answer 5:
P(Q) =37
Step-by-step explanation:
Given values in the figure that,
Q (Q) = 53
Equation of that make a combination of 180 degrees.
R(Q)+P(Q) +Q(Q) =180
90 +P(Q)+53 =180
P(Q) = 180 -143
P(Q) =37
