Use the Dilution Equation: [tex]\textbf{M1*V1} = \textbf{M2*V2}[/tex]
1). Plug in M1 , V1 and V2 into the Equation:
[tex](5.75M)(x) = (1.00M)(2.00L)[/tex]
2.) Solve for X:
[tex]x = \frac{(1.00M)(2.00L)}{5.75M}[/tex]
[tex]x = .347 \ Liters \ or \ 347ml [/tex]
Answer: 347ml of formic acid are needed
0.35L of a 5.75 M Formic acid solution should be used to prepare 2.00L of a 1.00M formic acid solution.
The volume of a diluted solution can be calculated using the following expression:
C1V1 = C2V2
where;
5.75 × V1 = 1 × 2
5.75V1 = 2
V1 = 2 ÷ 5.75
V1 = 0.35L
Therefore, 0.35L of a 5.75 M Formic acid solution should be used to prepare 2.00L of a 1.00M formic acid solution.
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