Calculate the concentration of h+ ions in a 0.010 m aqueous solution of sulfuric acid.express your answer to three decimal places and include the appropriate units.

Respuesta :

Assuming that the concentration is given as 0.010M (there is a big difference between m and M):

Sulfuric Acid (H2SO4) is a strong acid, and thus will completely dissociate into ions in solution.  This will result in [tex]2 H^{+}_{(aq)} + SO_{4}^{2-} _{(aq)}[/tex]

For each mole of H2SO4, there will be 2 moles of H+.  So, [H+] = 0.0200M

The concentration of hydrogen ion, H⁺ in a 0.01 M aqueous solution of sulfuric acid, H₂SO₄ is 0.02 M

What is molarity?

Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

How to determine the concentration of H⁺

Dissociation equation

H₂SO₄(aq) —> 2H⁺(aq) + SO₄²¯(aq)

From the balanced equation above,

1 mole of H₂SO₄ contains 2 moles of H⁺

Therefore,

0.01 M H₂SO₄ will contain = 0.01 × 2 = 0.02 M H⁺

Thus, the concentration of hydrogen ion, H⁺ in the solution is 0.02 M

Learn more about molarity:

https://brainly.com/question/9468209