Evaluate 32y−3+53z\dfrac32y-3+\dfrac53z ​2 ​ ​3 ​​y−3+ ​3 ​ ​5 ​​z start fraction, 3, divided by, 2, end fraction, y, minus, 3, plus, start fraction, 5, divided by, 3, end fraction, z when y=6y=6 y=6 y, equals, 6 and z=3z=3 z=3 z, equals, 3 .

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Answer:

11.

Step-by-step explanation:

We are asked to evaluate the expression [tex]\frac{3}{2}y-3+\frac{5}{3}z[/tex], when y=6 and z=3.

To evaluate our expression at given values we will just substitute y=6 and z=3 in our given expression.

[tex]\frac{3}{2}*6-3+\frac{5}{3}*3[/tex]

According order of operations (PEMDAS) we will multiply or divide our expression from left to right.

[tex]3*3-3+5*1[/tex]

[tex]9-3+5[/tex]

[tex]6+5[/tex]

[tex]11[/tex]

Therefore, the value of our given expression at y=6 and z=3 is 11.

Answer:

11

Step-by-step explanation:

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