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Express the area of a rectangle with length 3x^2y3x ​2 ​​ y3, x, start superscript, 2, end superscript, y and width 4y^34y ​3 ​​ 4, y, start superscript, 3, end superscript as a monomial.

Respuesta :

Answer: Area of rectangle is [tex]12x^2y^6[/tex]

Step-by-step explanation:

Since we have given that

Length of rectangle is given by

[tex]3x^2y^3[/tex]

Width of rectangle is given by

[tex]4y^3[/tex]

As we know the formula for "Area of rectangle ":

[tex]Area=Length\times Breadth\\\\Area=3x^2y^3\times 4y^3\\\\Area=12x^2y^6[/tex]

Hence, Area of rectangle is [tex]12x^2y^6[/tex]

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