Answer: 1) The strength of the magnetic field is 2.8 T.
2) The magnetic force exerted on particle-2 is 0.12 N.
Answer:
Explanation:
According to physic's magnetic law, the relation between a magnetic force, velocity, charge and magnetic field of a particle is :[tex]F_{B} =|q|vBsin\alpha[/tex]; where q is the charge, v the velocity, B the magnetic field, alpha is the angle between the velocity and the force. This equation represents the force experienced by a charge that travel at certain velocity in a magnet field.
So, basically we just need to replace each variable and solve for particle 1. You can see in the figure that the first particle has an angle of 90°.
[tex]F_{B1} = q_{1} v_{1} B sin\alpha _{1} \\5.75x10^{-3}N= (2.7x10^{-6} C)(773\frac{m}{s} )B(sin90\°)\\B= \frac{5.75x10^{-3} N}{2.7x10^{-6}C(773\frac{m}{s} )(sin90\°) } =2.8T[/tex].
For the second particle, we do the same process, in this case the angle is gonna be 55°:
[tex]F_{B2} = q_{2}v_{2} B sin\alpha _{2} = (42x10^{-6}C )(1.21x10^{3} \frac{m}{s} )(2.8T)sin55\°=0.12T[/tex]
(It's important to notice that the problem specify that the second particle is inside the same magnetic field, that's why we can use the same magnitude in the calculations)
