Answer:
B. -900 kg-m/s2
Explanation:
First of all, we need to calculate the acceleration of the hockey player, which is given by:
[tex]a=\frac{v-u}{t}[/tex]
where
v = 12 m/s is the final speed
u = 18 m/s is the initial speed
t = 0.6 s is the time
Substituting into the formula, we find
[tex]a=\frac{12 m/s-18 m/s}{0.6 s}=-10 m/s^2[/tex]
And now we can calculate the force exerted by using Newton's second law:
[tex]F=ma[/tex]
where m=90 kg is the mass of the hockey player. Substituting into the formula, we find
[tex]F=(90 kg)(-10 m/s^2)=-900 N[/tex]
