Mg + HCl → MgCl2 + H2 How many liters of hydrogen gas is produced at 298 K and 0.990 atm if 6.00 moles of hydrochloric acid react with an excess of magnesium metal?

Respuesta :

Answer: 74.04 liters of hydrogen gas is produced.

Explanation:

[tex]Mg+2HCl\rightarrow MgCl_2+H_2[/tex]

According to reaction, 2 mol of HCl gas gives 1 moles of hydrogen gas, then 6 moles of HCl gas will give:[tex]\frac{1}{2}\times 6[/tex] moles of hydrogen gas that is 3 moles.

Pressure of the hydrogen gas at 298 K = 0.990 atm

Volume occupied by the hydrogen gas = V

Number of hydrogen has moles = 3 moles

PV=nRT

[tex]0.990 atm\times V=3 moles\times 0.0820 L atm/K mol\times 298 K[/tex]

V = 74.04 L

74.04 liters of hydrogen gas is produced.