Answer:
[tex]x=\frac{-3+-\sqrt{-7}}{2}[/tex]
Step-by-step explanation:
Given equation is [tex]x^2+3x+4=0[/tex]
Apply quadratic formula to solve for x
[tex]x=\frac{-b+-\sqrt{b^2-4ac}}{2a}[/tex]
The value of a=1, b=3 and c=4
Plug in all the values and solve for x
[tex]x=\frac{-b+-\sqrt{b^2-4ac}}{2a}[/tex]
[tex]x=\frac{-3+-\sqrt{3^2-4(1)(4)}}{2(1)}[/tex]
[tex]x=\frac{-3+-\sqrt{9-16}}{2}[/tex]
[tex]x=\frac{-3+-\sqrt{-7}}{2}[/tex]
The square root is negative . so it is complex
