Answer:
option (d) is correct.
if a line crosses the y-axis at (0, 1) and has a slope of [tex]\frac{4}{5}[/tex], then equation of line is 5y - 4x = 5.
Step-by-step explanation:
Given : if a line crosses the y-axis at (0, 1) and has a slope of [tex]\frac{4}{5}[/tex].
We need to find the equation of line.
Equation of line is of the form y = mx + c, where m is the slope of line and c is the y- intercept. that is the point where line meets y- axis.
Given y intercept at (0, 1 ) ⇒ c = 1
Also, slope m = [tex]\frac{4}{5}[/tex]
Substitute it in equation, we get ,
y = mx + c ⇒ [tex]y=\frac{4}{5}x+1[/tex]
Solving , we get equation of line as ,
5y = 4x + 5 ⇒ 5y - 4x = 5
Thus, option (d) is correct.
if a line crosses the y-axis at (0, 1) and has a slope of [tex]\frac{4}{5}[/tex], then equation of line is 5y - 4x = 5.
Answer:
Choice D is correct answer.
Step-by-step explanation:
From question statement, we observe that
Slope is given and a point is given .
slope = 4/5 and point is (0,1)
y = mx+c is equation of line where m is slope and c is y-intercept.
y-intercept is a point where the value of x is zero.
hence, y-intercept = c = 1
Putting the given values in formula, we have
y = (4/5)x+1
y =( 4x+5) / 5
5y = 4x+5
Adding -4x to both sides of above equations, we have
5y-4x = 4x+5-4x
5y-4x = 5 is equation of line that crosses the y-axis at (0,1) and has a slope of 4/5.
