Answer : This is a type of decomposition reaction. The mass of copper oxide produced would be, 159 grams
Solution : Given,
Mass of copper sulfate = 319.22 g
Molar mass of copper sulfate = 159.6 g/mole
Molar mass of copper oxide = 79.5 g/mole
First we have to calculate the moles of copper sulfate.
[tex]\text{Moles of }CuSO_4=\frac{\text{Mass of }CuSO_4}{\text{Molar mass of }CuSO_4}=\frac{319.22g}{159.6g/mole}=2moles[/tex]
Now we have to calculate the moles of copper oxide.
The balanced chemical reaction is,
[tex]CuSO_4(s)\rightarrow CuO(s)+SO_3(g)[/tex]
This reaction is a decomposition reaction in which the larger reactant molecule decomposes to give two or more new products.
From the reaction, we conclude that
As, 1 mole of copper sulfate decomposes to produce 1 mole of copper oxide
So, 2 moles of copper sulfate decomposes to produce 2 moles of copper oxide
Now we have to calculate the mass of copper oxide.
[tex]\text{Mass of }CuO=\text{Moles of }CuO\times \text{Molar mass of }CuO[/tex]
[tex]\text{Mass of }CuO=(2mole)\times (79.5g/mole)=159g[/tex]
Therefore, the mass of copper oxide produced would be, 159 grams
Answer: a) Decomposition
b) 159.0 g of CuO(s) would be produced.
Explanation:
Decomposition reaction is a chemical reaction in which one reactant gives two or more than two products. They are endothermic reactions as energy is required to break the bonds of the reactants.
[tex]CuSO_4(s)\rightarrow CuO(s)+SO_3(g)[/tex]
As can be seen from the given balanced reaction:
1 mole of [tex]CuSO_4[/tex] gives 1 mole of [tex]CuO[/tex].
Thus 159.6 g of [tex]CuSO_4[/tex] gives 79.5 g of [tex]CuO[/tex].
319.22 g of [tex]CuSO_4[/tex] will give=[tex]\frac{79.5}{159.6}\times 319.22=159.0g[/tex]of [tex]CuO[/tex].
