Respuesta :
Answer:
[tex]\frac{7}{16}[/tex]
Step-by-step explanation:
Halloween candy contains 3 fruit candies, 2 chocolates, 5 caramels and 6 sour chews
So, total candies = 3 fruit candies+2 chocolates+5 caramels + 6 sour chews
= 16
Thus total no. of candies = 16
Probability of occurring an event = [tex]\frac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]
To find the probability of getting caramel or chocolate :
Favorable events : 5 caramels + 2 chocolates = 7
Total events = Total candies = 16
So, probability of getting caramel or chocolate:
= [tex]\frac{7}{16}[/tex]
Hence ,The probability of getting caramel or chocolate is [tex]\frac{7}{16}[/tex]
Answer: Probability of getting caramel or chocolate is [tex]\frac{7}{16}[/tex]
Step-by-step explanation:
Since we have given that
Number of fruit candies = 3
Number of chocolates = 2
Number of caramels = 5
Number of sour chews = 6
Total number of items is given by
[tex]3+2+5+6\\\\=16[/tex]
Probability of getting caramel or chocolate is given by
[tex]P(Caramel)+P(Chocolate)\\\\=\frac{5}{16}+\frac{2}{16}\\\\=\frac{7}{16}[/tex]
Hence, Probability of getting caramel or chocolate is [tex]\frac{7}{16}[/tex]
