Respuesta :
Answer: The number of C-atoms in methylacetylene are [tex]2.746\times 10^{22}[/tex]
Explanation:
To calculate the number of atoms, we first need to calculate the number of moles. For that we use the equation of ideal gas, which is:
[tex]PV=nRT[/tex]
where,
P = pressure of the gas = 1 atm
V = Volume of the gas = [tex]340cm^3=0.34L[/tex] (Conversion Factor: [tex]1cm^3=0.001L[/tex] )
n = Number of moles = ?
R = gas constant = [tex]0.08205\text{ L atm }mol^{-1}K^{-1}[/tex]
T = temperature of the gas = [tex]0^oC=273K[/tex] (Conversion factor: [tex]T(K)=T(^oC)+273[/tex] )
Putting values in above equation, we get:
[tex]1atm\times 0.34L=n\times 0.08205\text{ L atm }mol^{-1}K^{-1}\times 273K\\\\n=0.0152mol[/tex]
According to the mole concept:
1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of atoms
As, 1 mole of methylacetylene contains [tex]3\times 6.022\times 10^{23}[/tex] number of C-atoms.
So, 0.0152 moles of methylacetylene contains [tex]0.0152\times 3\times 6.022\times 10^{23}=2.746\times 10^{22}[/tex] number of C-atoms.
Hence, the number of C-atoms in methylacetylene are [tex]2.746\times 10^{22}[/tex]
