Answer:
[tex]CF=\frac{35}{2}[/tex].
Step-by-step explanation:
The area of the square is=81 square units
⇒[tex](side)^{2}=81[/tex]
⇒[tex]side=9cm[/tex]
From figure, AB= 9cm, and it is given that AE=5cm, therefore EB=4cm.
Now, Area of triangle EBF=[tex]\frac{1}{2}{\times}base{\times}height[/tex]
53=[tex]\frac{1}{2}{\times}4{\times}BF[/tex]
[tex]BF=\frac{53}{2}[/tex]
As, BF=BC+CF
And BC is the sie of square which is equal to 9cm
Therefore, [tex]\frac{53}{2}=9+CF[/tex]
[tex]CF=\frac{35}{2}[/tex].
