In triangle ABC, find B, to the nearest degree, given a = 7, b = 10, and C is a right angle.
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Answer:
55°
Step-by-step explanation:
Since ΔABC is right we can use the tangent ratio to find ∠B
tanB = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{10}{7}[/tex], hence
B = [tex]tan^{-1}[/tex]([tex]\frac{10}{7}[/tex]) = 55°