Respuesta :
Answer:
97,99,101,103
Step-by-step explanation:
Let x = first odd integer
x+2 = 2nd odd integer
x+4 = 3rd odd integer
x+6 = 4th odd integer
Sum of 4 odd integers is 400
x+ (x+2) + (x+4)+(x+6) = 400
Combine like terms
4x +12 = 400
Subtract 12 from each side
4x+12-12 = 400-12
4x = 388
Divide by 4 on each side
4x/4 = 388/4
x=97
The first integer is 97
The 2nd is 97+2 =99
The third ix 97+4 = 101
The 4th is 97+6 = 103
Answer:
Step-by-step explanation:
Here is another method. It might be shorter. You can decide. Make sure that the numbers are odd by doing this
2k + 1 is one of the odd numbers. 2k is even. When you add 1 to 2k + 1 is odd.
2k - 1 is another member of this family
2k + 3 is a third member
2k - 3 is the fourth member.
When you add them, all the coefficients will cancel out.
2k + 1 + 2k - 1 + 2k - 3 + 2k + 3 = 400 Add
8k = 400 Divide by 8
k = 400/8
k = 50
2k + 1 = 2*50 + 1 = 100 + 1 = 101
2k - 1 = 2*50 - 1 = 100 - 1 = 99
2k + 3 = 2*50 + 3 = 103
2k - 3 = 2*50 - 3 = 97
You don't really need to use 2k. You can do the same thing with n - 1 and n + 1 and n - 3 and n + 3. The same thing will happen: all the coefficients will cancel.