Answer:
The equation of the line will be [tex]7y=(-5x)+51[/tex]
Step-by-step explanation:
If a line passes through two points (x,y) and (x',y') then slope of the line will be = [tex]\frac{y-y'}{x-x'}[/tex]
Now we know the points are (-3,4) and (4,-1) then the slope of the line will be =[tex]\frac{4-(-1)}{(-3-4)}[/tex]=[tex]\frac{5}{(-7)} =(-\frac{5}{7}[/tex])
We know that two parallel lines have the same slope then a line which is passing through a point (-1,8)will be =( [tex]-\frac{5}{7}[/tex])
Let the equation of the line is y=mx+c
Then by putting the value of x,y and m we can get the value of c.
[tex]8=(-\frac{5}{7})+c[/tex]
[tex]c=8-\frac{5}{7} \\c=\frac{56-5}{7} =\frac{51}{7}[/tex]
Then equation will be [tex]y=(-\frac{5}{7})x+\frac{51}{7}[/tex]
[tex]7y=(-5x)+51[/tex]