Find an equation of the line passing through the point (-1,8) and parallel to the line joining the points (-3,4) (4,-1).

I understand that parallel lines have the same slope. I am terrible at math so if anyone can write how to do this in steps it will be very much appreciated.

Respuesta :

Answer:

The equation of the line will be [tex]7y=(-5x)+51[/tex]

Step-by-step explanation:

If a line passes through two points (x,y) and (x',y') then slope of the line will be = [tex]\frac{y-y'}{x-x'}[/tex]

Now we know the points are (-3,4) and (4,-1) then the slope of the line will be =[tex]\frac{4-(-1)}{(-3-4)}[/tex]=[tex]\frac{5}{(-7)} =(-\frac{5}{7}[/tex])

We know that two parallel lines have the same slope then a line which is passing through a point (-1,8)will be =( [tex]-\frac{5}{7}[/tex])

Let the equation of the line is y=mx+c

Then by putting the value of x,y and m we can get the value of c.

[tex]8=(-\frac{5}{7})+c[/tex]

[tex]c=8-\frac{5}{7} \\c=\frac{56-5}{7} =\frac{51}{7}[/tex]

Then equation will be [tex]y=(-\frac{5}{7})x+\frac{51}{7}[/tex]

[tex]7y=(-5x)+51[/tex]