6.25 moles Al2O3
Since all provided numbers are moles, there is no need for conversion. Rather, use a molar ratio:
12.5 [tex]\frac{2 mol AL2O3}{4 mol Al}[/tex]
Multiply across the top, 12.5 x 2, which gives you 25, before dividing that by the denominator (4).
This gives you the final answer of 6.25 moles of Al2O3.
Hope this helps!
The mass of aluminum oxide formed with 12.5 moles of aluminum is 637.5 grams.
The stoichiometric law is given as the coefficient present in the element being equivalent to the moles of the elements in the reaction.
In the given balanced chemical equation, 4 moles of Al form 2 moles of aluminum oxide. The moles of aluminum oxide formed by 12.5 moles of Al are:
4 moles Al = 2 moles Al₂O₃
12.5 moles Al = 2/4 × 12.5 moles Al₂O₃
12.5 moles Al = 6.25 moles Al₂O₃
The molar mass of aluminum oxide is 102 g/mol. The mass of compound in 6.25 moles is:
Moles = Mass/Molar mass
6.25 moles = Mass/ 102 g/mol
Mass = 637.5 grams
The mass of aluminum oxide formed with 12.5 moles of aluminum is 637.5 grams.
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