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Find the area of a square with a side measure of 3x − 6 feet. Question 5 options: 9x2−36x+36 sq. ft. 9x2−6 sq. ft. 9x2+36x+36 sq. ft. 9x2+36 sq. ft.

Respuesta :

Answer:

9x^2 - 36x + 36 sq. ft.   (the first option).

Step-by-step explanation:

Area of a square of side  d = d^2.

So area of this square = (3x - 6)^2

=  (3x - 6)(3x - 6)

= 3x(3x - 6) - 6(3x - 6)

= 9x^2 - 18x - 18x + 36

= 9x^2 - 36x + 36 sq ft.

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