briannaparker11
contestada

At 325 k, the pressure inside a gas-filled container is 467 kpa. If the pressure inside decreases to 233 kpa, but the volume remains the same, what is the final temperature of the gas?

Respuesta :

According to Gay-Lussac’s law, for a fixed mass of gas of constant volume, the pressure is directly proportional to the absolute temperature

Therefore

P1/T1 = P2/T2

Where P1 is initial pressure and T1 is initial temperature

And P2 is final pressure and T2 is final temperature

Substituting these values in the equation

467 kPa / 325 K = 233 kPa / T2

T2 = 162 K

The final temperature of the gas is 162 K

mahima6824soni

The final temperature of the gas will be 162 k.

What is Gay-Lussac's Law?

At constant volume, the pressure of the mass varies with the absolute temperature.

By the formula:

[tex]\dfrac{P1}{T1} = \dfrac{ P2}{T2}[/tex]

Where P1 is initial pressure and P2 is the final pressure

T1 is initial temperature and T2 is the final temperature

Putting the values:

[tex]\dfrac{467\; kpa}{467\; kpa} = \dfrac{ 233\; kPa }{T2}[/tex]

T2 = 162 K

Thus, the final temperature is 162 K

Learn more about Gay-Lussac's Law, here:

https://brainly.com/question/1358307

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