According to the fundamental theorem of algebra how many zeros does the function f(x)=15x^23+41x^19+13x^5-10

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11-01-2019
Mathematics

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According to the fundamental theorem of algebra how many zeros does the function f(x)=15x^23+41x^19+13x^5-10

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Аноним Аноним · Answer 1 · 2019-01-11T15:38:34+01:00

Аноним Аноним

11-01-2019

According to the fundamental theorem of algebra, that function has 23 zeros.
Whatever degree the polynomial is, that is how many zeros it will have.
Hope I helped!

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