Respuesta :
In the 9th year, the population of Franklin will exceed Chester.
We have two equations in this problem.
y = 20000(1.05)^x
y = 25000 + 500x
There are a few options to determine the answer.
1) Create a chart for each city.
2) Use a graphing calculator to graph them.
3) Solve the equation to determine when they are equal.
Answer:
-The first year in which Franklin's sign will show a larger number than Chester's sign will be the 9th year.
Explanation:
Year 1:
-Franklin 20,000
-Chester 25,000
Year 2:
-Franklin 20,000 + (20,000 x 5 / 100): 21,000
-Chester 25,000 + 500: 25,500
Year 3:
-Franklin 21,000 + (21,000 x 5 / 100): 22,050
-Chester 25,500 + 500: 26,000
Year 4:
-Franklin 22,050 + (22,050 x 5 / 100): 23,158
-Chester 26,000 + 500: 26,500
Year 5:
-Franklin 23,158 + (23,158 x 5 / 100): 24,316
-Chester 26,500 + 500: 27,000
Year 6:
-Franklin 24,318 + (24,318 x 5 / 100): 25,534
-Chester 27,000 + 500: 27,500
Year 7:
-Franklin 25,534 + (25,534 x 5 / 100): 26,811
-Chester 27,500 + 500: 28,000
Year 8:
-Franklin 26,811 + (26,811 x 5 / 100): 28,152
-Chester 28,000 + 500: 28,500
Year 9:
-Franklin 28,152 + (28,152 x 5 / 100): 29,560
-Chester 28,500 + 500: 29,000