A 15 ft. telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42 angle. How long is the wire, and what is the distance from the base of the pole to the spot where the wire touches the ground?
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Answer:
The correct option is 1.
Step-by-step explanation:
The height of the pole is 15 ft and the wire and the ground form a 42 angle.
Let the length of wire be x and the distance from the base of the pole to the spot where the wire touches the ground be y.
[tex]\sin\theta=\frac{Perpendicular}{Hypotenuse}[/tex]
[tex]\sin(42^{\circ})=\frac{15}{x}[/tex]
[tex]x=\frac{15}{\sin(42^{\circ})}[/tex]
[tex]x=22.417148248[/tex]
[tex]x\approx 22.4[/tex]
Therefore the length of wire is 22.4 ft.
[tex]\tan\theta=\frac{Perpendicular}{Base}[/tex]
[tex]\tan(42^{\circ})=\frac{15}{y}[/tex]
[tex]y=\frac{15}{\tan(42^{\circ})}[/tex]
[tex]y=16.6591877224[/tex]
[tex]y=16.7[/tex]
Therefore the distance from the base of the pole to the spot where the wire touches the ground is 16.7 ft.
Option 1 is correct.