Answer:
A C B
Step-by-step explanation:
In sequence A. the numbers are being divided by 4.
In sequence B. the numbers are being multiplied by -3
In sequence C. the numbers are being add by 4
So the ratio from least to greatest would be A C B
Answer:
Sequence B, Sequence A, Sequence C
Step-by-step explanation:
Common ratio of a geometric sequence is the ratio of a term and its previous term of the sequence.
Thus, the common ratio of the sequence A: 160,40,10,2.5,...
[tex]r_1=\frac{40}{160}=\frac{1}{4}[/tex]
The common ratio of the sequence B: -21,63,-189,567,...
[tex]r_2=\frac{63}{-21}=-3[/tex]
The common ratio of the sequence C : 8,12,18,27,....
[tex]r_3=\frac{12}{8}=\frac{3}{2}[/tex]
Since, -3 < [tex]\frac{1}{4}[/tex] < [tex]\frac{3}{2}[/tex]
Thus,
[tex]r_2 < r_1 < r_3[/tex]
Hence, the order the sequences from least common ratio to the greatest common ratio is,
Sequence B, Sequence A, Sequence C
