Answer:
Consistent and dependent
Step-by-step explanation:
We are given the following equation:
1. [tex]3x+6y-12z=36[/tex]
2. [tex]x+2y-4z=12[/tex]
3. [tex]4x+8y-16z=48[/tex]
For equation 1 and 3, if we take out the common factor (3 and 4 respectively) out of it then we are left with [tex]x+2y-4z=12[/tex] which is the same as the equation number 2.
There is at least one set of the values for the unknowns that satisfies every equation in the system and since there is one solution for each of these equations, this system of equations is consistent and dependent.
