The enthalpy of combustion of magnesium is -601.3 kj/mol
calculation
ΔH = cΔT
C( heat capacity) =5,760 j/°c
ΔT = 0.570°c
ΔH = 5760 j/°c x 0.570 °c = 3283.2 j
convert 3283.2 j into Kj
1 kj = 1000 j
kj ? =3283.2 j
by cross multiplication
={ (3283.2 j x 1 kj) / 1000 j} =3.2832 kj
Find the moles of Mg
moles = mass÷ molar mass
from periodic table the molar mass of Mg = 24.3 g/mol
= 0.1326 g÷ 24.3 g/mol =0.00546 moles
find ΔH in KJ/mol
= 3.2832 kj/ 0.00546 moles = 601.3 Kj/mol
since heat is released during combustion the ΔH is = - 601.3 kj/mol